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x^2+58x+14=0
a = 1; b = 58; c = +14;
Δ = b2-4ac
Δ = 582-4·1·14
Δ = 3308
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3308}=\sqrt{4*827}=\sqrt{4}*\sqrt{827}=2\sqrt{827}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-2\sqrt{827}}{2*1}=\frac{-58-2\sqrt{827}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+2\sqrt{827}}{2*1}=\frac{-58+2\sqrt{827}}{2} $
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